X^2-2x=(x+2)(x-3)

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Solution for X^2-2x=(x+2)(x-3) equation: 



X^2-2X=(X+2)(X-3)

We move all terms to the left:

X^2-2X-((X+2)(X-3))=0

We multiply parentheses ..

X^2-((+X^2-3X+2X-6))-2X=0



We calculate terms in parentheses: -((+X^2-3X+2X-6)), so:

(+X^2-3X+2X-6)

We get rid of parentheses

X^2-3X+2X-6

We add all the numbers together, and all the variables

X^2-1X-6

Back to the equation:

-(X^2-1X-6)



We add all the numbers together, and all the variables

X^2-2X-(X^2-1X-6)=0

We get rid of parentheses

X^2-X^2-2X+1X+6=0

We add all the numbers together, and all the variables

-1X+6=0

We move all terms containing X to the left, all other terms to the right

-X=-6

X=-6/-1

X=+6

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